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The first ionisation potential of Na is ...

The first ionisation potential of `Na` is `5.1eV`. The value of eectrons gain enthalpy of `Na^(+)` will be

A

`-2.55 eV`

B

`-5.1eV`

C

`-10.2 eV`

D

`2.55 eV`

Text Solution

Verified by Experts

The correct Answer is:
B
`Na rarr Na^(+) +e^(-)., I.P. = +5.1 eV`
`Na^(+) +e rarr Na rarr Delta H_(eg) =- 5.1 eV`
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