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If electro negativity of x be 3.2 and th...

If electro negativity of x be 3.2 and that of y be 2.2 , the percentage ionic character of xy is

A

19.5

B

18.5

C

9.5

D

29.5

Text Solution

Verified by Experts

The correct Answer is:
A
`EN_(x) - EN_(y) = 3.2 - 2.2 = 1`.
`Delta = 1`
`[Delta =` difference of electronegativity values between x and y]
% ionic character `= 16 Delta +3.5 Delta^(2) = 19.5`
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