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Calculate the % ionic character for meta...

Calculate the % ionic character for metal fluoride where the electronegativity of electropositive element is 2.1:

A

`43.03%`

B

`56.8%`

C

`50%`

D

`12%`

Text Solution

Verified by Experts

The correct Answer is:
A

% ionic character `= 16 (4-2.1) +3.5 (4-21)^(2) = 43.03%`
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GRB PUBLICATION-PERIODIC TABLE-E.Electronegativity
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  7. Which of the following is correct option? (p) Same number of electro...

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  12. Which element's electronegativity is closest to that of S?

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  13. Which atom has the highest electronegativity?

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  15. In which molecule does the chlorine have the most positive partial cha...

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