If `3e^(-)` can be accomodated in each orbital then how many elements will be present in the 7th period of periodic table?

Explanation

To determine how many elements will be present in the 7th period of the periodic table if 3 electrons can be accommodated in each orbital, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Concept of Orbitals**:
- In atomic theory, orbitals are regions around the nucleus where electrons are likely to be found. Each orbital can hold a certain number of electrons based on the Pauli exclusion principle.

2. **Identify the Number of Orbitals in the 7th Period**:
- The 7th period of the periodic table includes the filling of the 7s, 5f, 6d, and 7p orbitals.
- The total number of orbitals in the 7th period can be calculated as follows:
- 7s: 1 orbital
- 5f: 7 orbitals
- 6d: 5 orbitals
- 7p: 3 orbitals
- Total orbitals = 1 (7s) + 7 (5f) + 5 (6d) + 3 (7p) = 16 orbitals.

3. **Calculating the Total Number of Electrons**:
- If each orbital can accommodate 3 electrons, then the total number of electrons that can be accommodated in the 7th period is:
- Total electrons = Number of orbitals × Electrons per orbital
- Total electrons = 16 orbitals × 3 electrons/orbital = 48 electrons.

4. **Determining the Number of Elements**:
- Each element corresponds to one electron in this hypothetical scenario. Therefore, the number of elements in the 7th period would also be equal to the total number of electrons.
- Thus, the number of elements present in the 7th period = 48.

### Final Answer:
- If 3 electrons can be accommodated in each orbital, there will be **48 elements** present in the 7th period of the periodic table.