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Fe^(2+) does not give prussian blue colo...

`Fe^(2+)` does not give prussian blue colour with `K_(4)[Fe(CN)_(6)]` but on its reaction with (X), prussian blue colour appears (X) can be:

A

`MnO_(4)^(-)//H^(+)`

B

`Zn//NaOH`

C

`NH_(3)(aq)`

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
A
`Fe^(2+) overset(MnO_(4)^(-))underset(H^(+))rarr Fe^(3+) overset(K_(4)[Fe(CN)_(6)])rarr underset(("Prussian blue ppt"))(Fe_(4)[Fe(CN)_(6)]_(3)darr)`
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