Describe the change in hybridisation (if any) of the `Al` atom in the following:
`AlCl_(3)+Cl^(ө)rarr AlCl_(4)^(ө)`

Explanation

In `AlCl_(3),` the central Al atom is `sp^(2)` hybridised while in the ion `[AlCl_(4)]^(-),` it has `sp^(3)` hybridisation.
`underset(H=1//2[3+3-0+0]=3(sp^(2)))(AlCl_(3))" "underset(H=1//2[3+4-0+1]=4(sp^(2)))([AlCl_(4)]^(-))`