Is there any change in hybridisation of the `B` and `N` atom as a result of the following reaction?
`BF_(3)+NH_(3)rarr F_(3)B.NH_(3)`

Explanation

In `BF_(3),` B atom is `sp^(2)` hybridised. It froms an addition compound with `overset(* *)NH_(3)` (Where N atom is `sp^(3)` hybridised). In doing so it takes up an electron pair from `NH_(3).` This indicated that B atom undergoes a charge in hybridisation from `sp^(2)` to `sp^(3).` At the same there is no change in hybridisation of N atom.