Which of the following is a correct set with respect to molecule, hybridization, and shape?

Options

A. `BeCl_(2) : sp^(2)` linear
B. `BeCl_(2) : sp^(2),`triangular planar
C. `BCl_(3) : sp^(2),` triangular planar
D. `BCl_(3) : sp^(3)` tetrahedral.

Answer

C

Explanation

Hybridistaion of Be atom in `BeCl_(2)`
`=1/2[2+2-0+0]=4/2=2` (sp linear)
Hybridisation of B atom in `BCl_(3)`
`=1/3[3+3-+0]`
`=6/2=3(sp^(2)."trigonal planar")`
(c ) is correct answer