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Number of antibonding electrons in O(2)^...

Number of antibonding electrons in `O_(2)^(-)` molecular ion is :

A

8

B

6

C

7

D

4

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The correct Answer is:
To determine the number of antibonding electrons in the molecular ion \( O_2^- \), we can follow these steps: ### Step 1: Determine the Total Number of Electrons Each oxygen atom has 8 electrons, and since there are two oxygen atoms in \( O_2 \), we start with: \[ 8 \text{ (from O)} \times 2 = 16 \text{ electrons} \] However, since we have a negative charge on the ion (\( O_2^- \)), we need to add one more electron: \[ 16 + 1 = 17 \text{ total electrons} \] ### Step 2: Draw the Molecular Orbital Diagram In the molecular orbital theory, the molecular orbitals for \( O_2 \) can be arranged as follows: 1. \( \sigma_{1s} \) (bonding) 2. \( \sigma^*_{1s} \) (antibonding) 3. \( \sigma_{2s} \) (bonding) 4. \( \sigma^*_{2s} \) (antibonding) 5. \( \sigma_{2p_z} \) (bonding) 6. \( \pi_{2p_x} \) and \( \pi_{2p_y} \) (bonding) 7. \( \pi^*_{2p_x} \) and \( \pi^*_{2p_y} \) (antibonding) 8. \( \sigma^*_{2p_z} \) (antibonding) ### Step 3: Fill the Molecular Orbitals with Electrons We fill the molecular orbitals with the 17 electrons according to the Aufbau principle, Hund's rule, and the Pauli exclusion principle: 1. Fill \( \sigma_{1s} \) with 2 electrons 2. Fill \( \sigma^*_{1s} \) with 2 electrons 3. Fill \( \sigma_{2s} \) with 2 electrons 4. Fill \( \sigma^*_{2s} \) with 2 electrons 5. Fill \( \sigma_{2p_z} \) with 2 electrons 6. Fill \( \pi_{2p_x} \) and \( \pi_{2p_y} \) with 4 electrons (2 in each) 7. Fill \( \pi^*_{2p_x} \) and \( \pi^*_{2p_y} \) with 3 electrons (2 in one and 1 in the other) ### Step 4: Count the Antibonding Electrons Now we can count the number of electrons in the antibonding orbitals: - \( \sigma^*_{1s} \): 2 electrons - \( \sigma^*_{2s} \): 2 electrons - \( \pi^*_{2p_x} \): 2 electrons - \( \pi^*_{2p_y} \): 1 electron Adding these gives: \[ 2 + 2 + 2 + 1 = 7 \text{ antibonding electrons} \] ### Final Answer The number of antibonding electrons in the \( O_2^- \) molecular ion is **7**. ---

To determine the number of antibonding electrons in the molecular ion \( O_2^- \), we can follow these steps: ### Step 1: Determine the Total Number of Electrons Each oxygen atom has 8 electrons, and since there are two oxygen atoms in \( O_2 \), we start with: \[ 8 \text{ (from O)} \times 2 = 16 \text{ electrons} \] However, since we have a negative charge on the ion (\( O_2^- \)), we need to add one more electron: ...
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DINESH PUBLICATION-CHEMICAL BONDING AND MOLECULAR STRUCTURE -JEE (MAIN) & OTHER ENGINEERING ENTRANCE EXAMINATIONS
  1. N(2) and O(2) are converted into monocations, N(2)^(+) and O(2)^(+) r...

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  2. A neutral molecule XF(3) has a zero diple moment. The element X is mos...

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  3. The molecule having smallest bond angle is

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  4. Stability of the species Li(2), Li(2)^(-) and Li(2)^(+) increases in t...

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  5. In the of the following pairs of molecules /ions both the species are ...

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  6. Which of the following is diamagnetic ?

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  7. Number of antibonding electrons in O(2)^(-) molecular ion is :

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  8. The pair of compounds having identical shapes for their molecules is:

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  9. Which of the following properties is not shown by NO ?

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  10. In the formation of pi-bond, the atomic orbitals overlap in such a way...

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  11. The attractive force which holdes various constituents togrther in dif...

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  12. Which of the following stability order is correct ?

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  13. The number of lone pairs of electrons on central atom of H(2)O,SnCl(2)...

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  14. Which of the following changes in the respectively bond N(2) and F(2) ...

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  15. The species in which the N-atom is in a state of sp hybridisation is

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  16. Which of the following have least dipole moment?

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  17. The increassing order of bond order of O(2),O(2)^(+),O(2)^(-)and O(2)^...

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  18. HCl gas is covalent and NaCl is an ionic compound. This is because

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  19. Out of SO(2),BeCl(2),O(3),H(2)O and HgCl(2), the linear species are:

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  20. Hybridisation and shape of BrF(5) is :

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