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The hybridization of atomic orbitals of ...

The hybridization of atomic orbitals of nitrogen is `NO_(2)^(+), NO_(3)^(-)`, and `NH_(4)^(+)` respectively are

A

`sp,sp^(3),and sp^(2)` respectively

B

`sp,sp^(2),and sp^(3)` respectively

C

`sp^(2),sp,and sp^(3)` rspectively

D

`sp^(2),sp^(3),and sp` respectively

Text Solution

Verified by Experts

The correct Answer is:
B

`NO_(2)^(+)=1//2[5+0-1+0]=4//2=sp`
`NO_(3)^(-)=1//2[5+0-0+1]=6//2=sp^(2)`
`NH_(4)^(+)=1//2[5+4-1+0]=8//4=sp^(3)`
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