The types of hybrid orbitals of nitrogen in `NO_(2)^(+), NO_(3)^(+) and NH_(4)^(+)` respectively are expented to be :

Options

A. `sp,sp^(2)and sp^(2)`
B. `sp,sp^(2)and sp^(3)`
C. `sp^(2),spand sp^(3)`
D. `sp^(2),sp^(3)and sp`

Answer

B

Explanation

`NO_(2)^(+):H=^(1//2)[5+0-1+0]=2(sp)`
`NO_(3)^(-):H=^(1//2)[5+0-0+1]=6(sp^(2))`
`NO_(4)^(+):H=^(1//2)[5+4-1+0]=4(sp^(3))`