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A weather ballon has a volume of 175 dm^...

A weather ballon has a volume of `175 dm^(3)` when filled with hydrogen gas at a pressure of `1*0` bar. Caculate the volume of the bolloon when it rises to a height where the atmospheric pressure is `0*8` bar. Assume that temperature is constant.

Text Solution

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From the given data : `P_(1) = 1` bar , `P_(2) = 0.8` bar
`V_(1) = 175 dm^(3) , V_(2) = ?`
since the temperature is constant, Boyle's Law can be applied
`P_(1)V_(1) = P_(2)V_(2)` or `V_(2) = (P_(1)V_(1))/(P_(2))` or `V_(2) = ((1 "bar") xx (175 "dm"^(3)))/((0.8 "bar")) = 218.75 dm^(3)`
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