A ballon is filled with hydrogen at room temperature. It will burst if pressure exceeds `0.2 "bar"`. If at `I` bar pressure, the gas occupies `2.27 L` volume, up to what volume can the balloon be expanded?

Explanation

From the given data : `P_(1) = 1` bar , `P_(2) = 0.2` bar
`V_(1) = 2.27 L , V_(2) = ?`
At constant temperature, Boyle's Law can be applied
`P_(1)V_(1) = P_(2)V_(2)` or `V_(2) = (P_(1)V_(1))/(P_(2)) = ((1 "bar") xx (2.27 L))/((0.2 "bar")) = 11.35 L`
In order that the balloon may not burst, its volume must be kept less than `11.35 L`