A certain amount of a gas at `27^(@)C` and `1` bar pressure occupies a volume of `25 m^(3)`. If the pressure is kept constant and the temperature is raised to `77^(@)C` what will be the volume of the gas?

Explanation

From the available data : `V_(1) = 25 m^(3) , T_(1) = 27 + 273 = 300 K`
`V_(2) = ? , T_(2) = 77 + 273 = 350 K`
Since the pressure of gas is constant, Charles's law is applicable.
`(V_(1))/(V_(2)) = (T_(1))/(T_(2))` or `V_(2) = (V_(1) xx T_(2))/(T_(1))`
`V_(2) = ((25 m^(3)) xx (350 K))/((300 K)) = 29.17 m^(3)`