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A gas at a pressure of 5.0 atm is heated...

A gas at a pressure of 5.0 atm is heated from `0^(@)C` to `546^(@)C` and simultaneously compressed to one-third of its original volume. Hence, final pressure is:

Text Solution

Verified by Experts

From the The available data :
`V_(1) = V dm^(3)` , `V_(2) = (V)/(3) dm^(3)`
`P_(1) = 5` bar , `P_(2) = ?`
`T_(1) = 0 + 273 = 273 K` , `T_(2) = 546 + 273 = 819 K`.
According to Gas equation, `(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))` or `P_(2) = (P_(1)V_(1)T_(2))/(T_(1)V_(2))`
By substituting the values, `P_(2) = ((5 "bar") xx (V dm^(3)) xx (819 K))/((273 K) xx (V//3 dm^(3))) = 45` bar
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