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Calculate the mass of 0.120 dm^(3) of N(...

Calculate the mass of `0.120 dm^(3)` of `N_(2)` at `150^(@)C` and `0.987` bar pressure.

Text Solution

Verified by Experts

Step I. Calculating of no. of moles of `N_(2)`,
`P = 0.987` bar , `V = 0.120 dm^(3)`
`T = (150 + 273) = 423 K` , `R = 0.083 "bar" dm^(3)K^(-1) mol^(-1)`
According to ideal gas equation, `PV = nRT`
`n = (PV)/(RT) = ((0.987 "bar") xx (0.120 dm^(3)))/((0.083 "bar" dm^(3) K^(-1) mol^(-1)) xx (423 K)) = 0.0034` mol
Step II. Calculation of mass of `N_(2)`.
No. of mass of `N_(2) (N) = 0.0034` mol
Molar mass of `N_(2)(M) = 28 gmol^(-1)`
Mass of `N_(2) = n xx M = (0.0034 mol) xx (28 g mol^(-1)) = 0.095 g`
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