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A vessel contains 14g of hydrogen and 96...

A vessel contains `14g` of hydrogen and `96g` of oxygen at STP.
(a) Find the volume of the vessel.
(b) Chemical reaction is induced by passing electric spark in the vessel till one of the gases is consumed, The temperature is brought back to its starting value `273K`. Find the pressure in the vessel.

Text Solution

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Step I. Calculation of volume of the container.
No. of moles of `H_(2) = (14 g)/((2 g mol^(-1))) = mol`
No. of moles of `O_(2) = (96 g)/((32 gmol^(-1))) = 3` mol
Total no. of moles in the container `= (7+3) = 10` mol
According to ideal gas equation, `PV = nRT` or `V = (nRT)/(P)`
Under S.T.P. conditions `V = ((10 mol) xx (0.083 dm^(3) "bar" K^(-1) mol^(-1)) xx (273 K))/((1 "bar"))`
`= 226.59 dm^(3)`
Volume of container (Volume of gaseous mixture enclosed) `= 226.59 dm^(3)`
Step II. Calcualation of pressure in the container
`{:(underset(2 mol)(2H_(2)(g)),+,underset(1 mol)(O_(2))(g)rarr2H_(2)O(l)):}`
1 mole of `O_(2)` react with `H_(2) = 2` mol
3 moles of `O_(2)` react with `H_(2) = 6` mol
No. of mass of `H_(2)` left in the container
`= (7-6) = 1` mol
(Neglect the volume of the water is in the liquid state)
According to ideal gas equation
`P' = (n'RT)/(V), P = (nRT)/(V)`
`:. (P')/(P) = (n')/(n) = 1/10` or `P' = (P)/(10) = ((1 "bar"))/(10) = 0.1` bar
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