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The density of a gas is found to be 1.56...

The density of a gas is found to be `1.56 g dm^(-3)` at `0.98` bar pressure and `65^(@)C`. Calculate the molar mass of the gas.

Text Solution

Verified by Experts

From the available data :
`rho = 1.56 g dm^(-3) , P = 0.98 "bar"`
`T = (65+273) = 338 K, R = 0.0821 dm^(3) "bar" K^(-1) mol^(-1)`.
We know that, `M = (rhoRT)/(P) = ((1.56 g dm^(-3)) xx (0.0821 dm^(3) "bar" K^(-1) mol^(-1)) xx (338 K))/((0.98 "bar"))`
`= 44.66 g mol^(-1)`
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