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The pressure of a mixture of H(2) and N(...

The pressure of a mixture of `H_(2)` and `N_(2)` in a container is `1200` torr. The partical pressure of nitrogen in the mixture is `300` torr. What is the ratio of `H_(2)` and `N_(2)` molecules in the mixture?

Text Solution

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Total pressure of mixture `= 1200` torr
Partial pressure of `N_(2)(pH_(2)) = 1200-300 = 900` torr
According to ideal gas equation `PV = nRT`
`p_(H_(2)) = (n_(H_(2)) RT)/(V) = 900` torr
`p_(N_(2)) =(n_(N_(2)) RT)/(V) = 300` torr
Divide (i) by (ii) `(p_(H_(2)))/(p_(N_(2))) = (n_(H_(2)))/(n_(N_(2))) = (900)/(300) = 3/1 :. p_(H_(2)) : n_(N_(2)) :: 3 : 1`
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