What volume of carbon dioxide measured at `27^(@)C` and `746.7 mm` pressure will be obtained by treating `10.0 g` of pure marble with dilute hydrochloric acid ? (Aqueous tension at `27^(@)C` is `26.7 mm`)

Explanation

Step I. Calculation of volume of `CO_(2)` at N.T.P.
`underset(=100 g) underset(40+12+48)(CaCO_(2))overset("Heat")rarrCaO + underset(22400 cm^(3))(CO_(2))`
`100g` of `CaCO_(3)` evolve `CO_(2)` upon heating `= 22400 cm^(3)`
`10 g` of `CaCO_(3)` evolve `CO_(2)` upon heating `= (22400)/(100) xx 10 = 22400 cm^(3)`
Step II. Calculation of volume of `CO_(2)` under experimental conditions
`{:(V_(1)=2240cm^(3),,V_(2)=?),(P_(1)=760mm,,P_(2)=746.7-26.7=720mm),(T_(1)=273K,,T_(2)=27+273=300 K):}`
According to gas equation, `(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))` or `V_(2) = (P_(1)V_(1)T_(2))/(T_(1)P_(2))`
By substituting the valus, `V_(2) = ((760 mm) xx (2240 cm^(3)) xx (300 K))/((273 K) xx (720 mm)) = 2598.3 cm^(3)`