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Calculate the average kinetic energy of...

Calculate the average kinetic energy of one mole of `CO_(2)` at `450 K` in Joules.

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Average kinetic energy `(K.E.) = 3/2 RT` , (for 1 mole of the gas)
`R = 8.314 J mol^(-1)K^(-1) , T = 450 K`
`KE = 3/2 xx (8.314 J mol^(-1)K^(-1)) xx (450 K) = 5411.95 J mol^(-1)`
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