If volume mass and temperture of two gases `H_(2)` and `O_(2)` kept in spearate vessles are the same, in which vessel the pressure will be greater and how many times ?

Explanation

According to ideal gas equation.
`PV = nRT` or `P = n/V RT = (WRT)/(MV)`.
For the two gases, W,R,T and V are same.
`:. P prop (1)/(M)` , (Where M is the molar mass of the gas)
`(P_(H_(2)))/(P_(O_(2))) = (M_(O_(2)))/(M_(H_(2))) = (32)/(2) = 16` or `P_(H_(2)) = 16 xx P_(O_(2))`
This shows that the pressure exerted by `H_(2)` gas will be sixteen more than the pressure exerted by oxygen.