At what temperature in centigrade will the volume of a gas at `0^(@)C` double itself, pressure remaining constant?

Answer

`273^(@)C`

Explanation

`V_(1) = V mL , V_(2) = 2VmL`
`T_(1) = 0 + 273 = 273 K` ,
Since pressure of the gas is constant, Charles' Law is applicable.
`(V_(1))/(T_(1)) = (V_(2))/(T_(2))` or `T_(2) = (V_(2) xx T_(1))/(V_(1)) = ((2 V mL) xx (273 K))/((V mL)) = 546 K = 273^(@)C`.