A gas occupies a certain volume at `600` torr pressure and `27^(@)C`. If pressure is reduced to `500` torr, what temperature should be employed to keep the volume constant?

Answer

`-23^(@)C`

Explanation

`P_(1) = 600` torr , `P_(2) = 500` torr
`T_(1) = 27 + 273 = 300 K` , `T_(2) = ?`
According to Gay Lussac's Law,
`(P_(1))/(P_(2)) = (T_(1))/(T_(2))` or `T_(2) = (P_(2) xx T_(1))/(P_(1)) = ((500 ml) xx (300 K))/((600 mL)) = 250 K = -23 ^@C`