At `27^(@)C` and one bar pressure a has volume `VL`. What will be its volume at `177 ^(2)C` and under pressure of `1.5"bar"`?

Answer

VL

Explanation

`V_(1) , = VL , V_(2) , = ?`
`P_(1) = 1 "bar" , P_(2) = 1.5 "bar"`
According to ideal gas equation,
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))` or `V_(2) = (P_(1)V_(1)T_(2))/(T_(1)P_(2)) = ((1 "bar") xx (VL) xx (450 K))/((300 K) xx (1.5 K)) = VL`