Calculate the pressure of `10^(23)` molecules of sulphur dioxide `(SO_(2))` when enclosed in a vessel of `2.5 L` capacity at a temperature of `27^(2)C`.

Answer

`1.653 xx 10^(-1) atm`

Explanation

According to ideal gas equation :
`PV = nRT` , or `P = (nRT)/(V)`
`n = (1 xx 10^(22))/(N_(O)) = (1 xx 10^(22))/(6.022 xx 10^(23)) = 1.66 xx 10^(-2) mol, V = 2.5 L`
`R = 0.083 L "bar" K^(-1) mol^(-1), T = 27 + 273 = 300 K`
`P = ((1.66 xx 10^(-2) mol) xx (0.083 L "bar" K^(-1) mol^(-1)) xx (300 K))/((2.5 L)) = 1.653 xx 10^(-1)` atm