A 10 litre flask contains 0.2 mole of methane, 0.3 mole of hydrogen and 0.4 mole of nitrogen at `25^(@)C`. What is the partial pressure of each component and what is the pressure inside the flask ?

Answer

`pCH_(4) = 0.489 atm, pH_(2) = 0.734 atm, pN_(2) = 0.979 atm, p_("Total") = 2.202 atm`

Explanation

Partial pressure of `CH_(4)(pCH_(4)) = (.^(n)CH_(4)RT)/(V) = (0.2 xx 0.0821 xx 298)/(10) = 0.489 atm`
Partial pressure of `H_(2) (pH_(2)) = (.^(n)H_(2)RT)/(V) = (0.3 xx 0.0821 xx 298)/(10) = 0.734 atm`
Partial pressure of `N_(2) (pN_(2)) = (.^(n)N_(2)RT)/(V) = (0.4 xx 0.0821 xx 298)/(10) = 0.979` atm
Total pressure `(p_("total")) = (0.489 + 0.734 + 0.979) = 2.202` atm