At `25^(@)C` and 760 mm of Hg pressure a gas occupies 600 mL volume. What will be its pressure at a height where temperature is `10^(@)C `and volume of the gas is 640 mL.

Answer

`676.64 mm`

Explanation

`{:("Initial Conditions",,"Final Conditions"),(V_(1)=600mL,,V_(2)=640 mL),(P_(1)=760 mm,,P_(2)=?),(T_(1)=25^(@)C=298K,,T_(2)=10^(@)C=283K):}`
Applying gas equation :
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))` or `P_(2) = (P_(1)V_(1)T_(2))/(T_(1)V_(2))`
`P_(2) = ((760 mm) xx (600 mL) xx (283 K))/((298 K) xx (640 mL)) = 676.64 atm`