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The rate of diffusion of a gas X is sqrt...

The rate of diffusion of a gas X is `sqrt(2)` times that of Y. If the molecular masss X is 16, what is the molecular mass of gas y?

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The correct Answer is:
`321`

`(r_(x))/(r_(y)) = sqrt(2), M = 16, M_(y) = ?`
Accoding to Graham's Law of diffusion.
`(r_(x))/(r_(y)) = sqrt((M_(y))/(M_(x)))=sqrt(2)` or `(M_(y))/(M_(x)) =2` or `M_(y) = 2 xx M_(x) = 2 xx 16 = 32`
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