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The kinetic energy of 4 mol of nitrogen...

The kinetic energy of `4` mol of nitrogen gas at `127^(@) C` is …….. `cal "(R = 2 cal mol^(-1) K^(-1))`

A

`4400` cals

B

`3200` cals

C

`4800` cals

D

`1524` cals

Text Solution

Verified by Experts

The correct Answer is:
C
`kE = (3)/(2) nRT`
`= 3/2 xx (4 "mol") xx (2 cal"mol"^(-1)K^(-1)) xx (400 K) = 4800` cals.
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