At `27^(@)C` under one atmosphere pressure, a gas occupies a volume of `V` L. In case the temperature is increased to `177^(@)C` and pressure to `1.5` bar, the corresponding volume will be :

Options

A. `V mL`
B. `2V mL`
C. `V//2 mL`
D. `V//3 mL`

Answer

A

Explanation

`V_(1) = V L , V_(2) = ?`
`P_(1) = 1 "bar" , P_(2) = 1.5 "bar"`
`T_(1) + 27 + 273 , T_(2) = 177 + 273`
`= 300 K` , `=450K`
According the ideal gas equation :
`(P_(1)V_(1))/(T_(1)) = (P_(2)V_(2))/(T_(2))` or `V_(2) = (P_(1)V_(1)T_(2))/(T_(1)P_(2))`
` = ((1 "bar")xx (VL) xx (450 K))/((300K) xx (1.5 "bar")) = VL`