Critical density of a gas having molecular mass `39 g mol^(-1)` is `0.1 g cm^(-3)`. Its critical volume in `L mol^(-1)` is

Options

A. `0.390`
B. `3.90`
C. `0.039`
D. `39.0`

Answer

A

Explanation

Critical density `= 0.1 g cm^(-3) = 100 gL^(-1)`
Critical volume `= ("Molecular mass")/("Critical density")`
`= ((39 mol^(-1)))/(100 gL^(-1)) = 0.39 L mol^(-1)`