An organic compound on analysis gave the following data:
(i). 0.25 gm of the compound on complete combustion gave 0.37 gm of `CO_2` and 0.2 gm of water.
(ii). 0.25 gm of the compound on analysis by Dumas method gave 32 ml of nitrogen gas at STP.
Calculate the percentages of `C,H,N` and `O `in the organic compounds.

Explanation

(i) Calculation of percentage of carbon.
Mass of the compound =0.25 g
Mass of carbon dioxide formed =0.37 g
Percentage of carbon `=12/44xx("Mass of "CO_(2))/("Mass of compound")xx100=12/44xx0.37/0.25xx100=40.36`
(ii) Calculation of percentage of hydrogen
Mass of the compound =0.25 g
Mass of water formed =0.20 g
Percentage of hydrogen `=2/18xx("Mass of "H_(2)O)/("Mass of compound")xx100=2/18xx0.20/0.25xx100=8.89`
(iii) Calculation of persentage of nitrogen.
Mass of the compound = 0.25 g
Volume of `N_(2)` evolved at N.T.P. = 32 mL
Percentage of nitrogen `=28/22400xx("Volume of "N_(2)" at N.T.P.")/("Mass of compound")xx100=28/22400xx32.0/0.25xx100=16.0`