In an estimation od sulphur by carius method, 0.2175 g of a compound gave 0.5825 g of barium sulphate. Calculate the percentage of sulphur in the compound.

Explanation

Mass of the compound `=0.2175 g`
Mass of barium sulphate `=0.5825 g`
`{:(BaSO_(4),equiv,S),((137+32+64)" parts",,"32 parts"),(233 g,,32 g):}`
233g of barium sulphate contain sulphur `=32 g`
0.5825 g of barium sulphate contain sulphur `=32/233xx0.5825 g`
Percentage of sulphur `=("Mass of sulphur")/("Mass of compound")xx100=32/233xx0.5825/0.2175xx100=36.78`.