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0.378 g od an organic compound containin...

0.378 g od an organic compound containing carbon and hydrogen was subjected to cobustion by Liebig's method , the `CO_(2)` and `H_(2)O`formed were passed through potash bulbs and `CaCl_(2)` (anhydrous) tube. At end of the experiment, the increase in the respective weights were 0.264 g and 0.162 g. Calculate the percentage of carbon and hydrogen.

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The correct Answer is:
`C = 19.05 %, H = 4.76 %`

Increase in weight of potash bulbs (mass pf `CO_(2)` evolved) `=0.264 g`
Increase in weight of `CaCl_(2)` tube (mass of `H_(2)O` forward) `=0.162 g`
`%` of `C=12/44xx("Mass of "CO_(2))/("Mass of compound")xx100=12/44xx0.264/0.378xx100= 19.05%`
`%` of `H=12/18xx("Mass of "H_(2)O)/("Mass of compound")xx100=2/18xx0.162/0.378xx100= 4.76 %`
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