A uniform wire of resistance `=3Omega` and length `l` is stretched to double its length. Now it is bent to form a circular loop and two point `P & Q` lies on the loop such that they subtend `60^(@)` angle at centre. The equivalent resistance between two point P & Q is:

A wire of resistance 1 Omega is stretched to double its length. Then its resistance becomes

If a wire of resistance 1Omega is stretched to double its length, then the resistnance will become

A metal wire of resistance 3Omega is elongated to make a uniform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60^(@) at the center, the equivalent resistance between these two points will be :

A metal wire of resistance 3 omega is elongated to make a unform wire of double its previous length. This new wire is now bent and the ends joined to make a circle. If two points on this circle make an angle 60^(@) at the centre, the equivalent resistance between these two points will be :

The resistance of a wire is 2 Omega . The wire is stretched to doubel its length. Now the resistance of the wire will become

A uniform wire of resistance R is stretched uniformly so that its length is doubled. Its new resistance is

A wire of resistance 4 Omega is stretched to four times of its original length resistance of wire now becomes

P and Q are two points on a uniform ring of resistance R. The equivalent resistance between P and Q is

A wire is bent in the form of a triangle now the equivalent resistance between its one end and the mid point of the side is