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0.2595 g of organic compound when treate...

0.2595 g of organic compound when treated by carius method gave 0.35 g of `BaSO_(4)`. Calculate the percentage of sulphur in the compound.

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The correct Answer is:
`18.52`
Percentage of sulphur `=32/233xx ("Mass of "BaSO_(4))/("Mass of compound")xx100=32/233xx0.35/0.2595xx100=18.52%`
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0.2595 gm of an organic substance when treated by carius method gave 0.35 gm of BaSO_4 . Calculate the percentage of sulphur in the compound?

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0.2595 g of an organic substance, when treated by carius method gave 0.25g of BaSO_(4) calculates the % of S in the compound.

0.395 g of an organic compound by Carius method for the estimation of sulphur gave 0.582 g of BaSO_4 . Calculate the percentage of sulphur in the compound.

0.395 g of an organic compound by Carius method for the estimation of S gave 0.582 g of BaSO_4 The percentage of S in the compound is

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