Electronegativity of carbon atoms depends upon their state of hybrisation. In which of the following compounds, the carbon marked with asterisk is most electronagative ?

Options

A. `CH_(3)-CH_(2)-^(**)CH_(2)-CH_(3)`
B. `CH_(3)-^(**)CH=CH-CH_(3)`
C. `CH_(3)-CH_(2)-C equiv^(**)CH`
D. `CH_(3)-CH_(2)-CH=^(**)CH_(2)`

Answer

C

Explanation

`- C equiv overset(**)(C)H` carbon is the most electronegative since it is sp hydridised and has maximum s-character. The release of `H^(+)` from `C - H` bond becomes easiest.