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A face-centred cubic element (atomic mas...

A face-centred cubic element (atomic mass `60`) has a cell edge of `400` pm. What is its density?

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Density of unit cell `(rho)=(ZxxM)/(a^(3)xxN_(0)xx10^(-30))`
According to available data,
Edge length (a) = 400 pm = 400
Atomic mass of element (M) = 60 u = `"60 g mol"^(-1)`
No. of atoms per unit cell (Z) = 4
Avogadro's Number `(N_(0))=6.022xx10^(23)"mol"^(-1)`
`"Density of unit cell"=(4xx("60 g mol"^(-1)))/((400)^(3)xx(6.022xx10^(23)"mol"^(-1))xx(10^(-30)"cm"^(3)))="6.23 g cm"^(-3)`
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