Home
Class 12
CHEMISTRY
KCl crystallizes int the same type of...

KCl crystallizes int the same type of lattic as done NaCl . Given that `r_(Na^(+))//r_(Cl^(-)) = 0.50` and `r_(Na^(+))//r_(K^(+)) = 0.70` , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

Text Solution

Verified by Experts

`(r_(Na^(+)))/(r_(Cl^(-)))=0.55, (r_(Na^(+)))/(r_(Cl^(-)))+1=1.55`
`(r_(K^(+)))/(r_(Cl^(-)))=0.74, (r_(K^(+)))/(r_(Cl^(-)))+1=1.74`
Dividing (ii) by (i), `(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))=(1.74)/(1.55)=1.122`
Promotional Banner

Topper's Solved these Questions

  • SOLID STATE

    DINESH PUBLICATION|Exercise PROBLEMS|71 Videos
  • SOLID STATE

    DINESH PUBLICATION|Exercise MULTIPLE CHOCIE QUESTION (TYPE-I)|63 Videos
  • SOLID STATE

    DINESH PUBLICATION|Exercise QUESTION FROM BOARD EXAMINATION|80 Videos
  • REDOX REACTIONS

    DINESH PUBLICATION|Exercise Ultimate Preparation|9 Videos
  • SOLUTIONS

    DINESH PUBLICATION|Exercise ULTIMATE PREPARATORY PACKAGE|10 Videos

Similar Questions

Explore conceptually related problems

KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

KCI crystallizes in the same type of lacttice as does NaCl . Given that (r_(Na^(o+)))/(r_(Cl^(Θ))) = 0.5 and (r_(Na^(o+)))/(r_(K^(o+))) = 0.7 Calculate (a) the ratio of side of the unit cell for KCl to that for NaCl , and (b) the ratio of density of NaCl to that KCl .

KCI cyrstallizes in the saem type of lattice as does NaCl. Given that (r_(Na^(o+))/(r_(Cl_(-)))=0.5 and (r_(Na^(o+)))/(r_(K^(o+)))=0.7 Calculate the ratio of side of the unit cell for KCl to that for NaCl.

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is