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Calcium crystallizesin fcc unit cell wit...

Calcium crystallizesin `fcc` unit cell with `0.556 nm`. Calculate the density if
a. It contains `0.2%` Frenkel defects
b. It contains `0.1%` Schottky defects

Text Solution

Verified by Experts

(i) Density in case of Frenkel defects. The Frenkel defects do not change the density because the number of atoms Per unit cell remains the same.
`rho=(ZxxM)/(a^(3)xxN_(0))=(4xx("40 g mol"^(-1)))/((0.556xx10^(-7)cm)^(3)xx(6.022xx10^(23)"mol^(-1)))`
`=1.5463"g cm"^(-3)`
(ii) Density in case Schottky defects. Due to Schottky defects, vacant spaces will decrease the number of atoms per unit cell.
`therefore" "Z=(4-(4xx0.1)/(100))=3.996`
`rho=(ZxxM)/(a^(3)xxN_(0))=((3.966)xx("40 g mol"^(-1)))/((0.556xx10^(-7)cm)^(3)xx(6.002xx10^(23)mol^(-1)))`
`=1.5448"g cm"^(-3)`
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