A solid compound `XY` has `NaCl` structure. If the radius of the cation is `100` pm, the radius of the anion `(Y^(-))` will be

Options

A. `275.1 "pm"`
B. `322.5 "pm"`
C. `241.5 "pm"`
D. `165.7 "pm"`

Answer

C

Explanation

For NaCl,
`r^(+)/r^(-)=0.414`
Radius of Cation `=100 "pm" ("given")`
`r^(-)=r^(+)/(0.414)=((100"pm"))/(0.414)=241.5"pm"`