Structure of a mixed oxide is cubic close packed the cubic unit cell of mixed oxide is composed of oxide ions. One fourth of the tetrahedral voids are occupied by divalent metal.A and the octahedral voids are occupied by a monvalent metal `B`. The formula of the oxide is :

Options

A. `ABO_(2)`
B. `A_(2)BO_(2)`
C. `A_(2)B_(3)O_(4)`
D. `AB_(2)O_(2)`

Answer

D

Explanation

No. of atoms `(O^(2-))` in ccp `=4`
No. of tetrahedral voids `=2xxN=8`
No. of `A^(2+)` ions `=8xx1/4=2`
No. of octahedral voids =No of `B^(+)` ions =4
Ratio , `O^(2-),A^(2+):B^(+)=4:2:4=2:1:2`
Formula of oxide `=AB_(2)O_(2)`