Suppose the mass of a single Ag atoms is 'm' Ag metal crystallises in fcc lattice with unit cell edge length 'a' The density of Ag metal in terms of 'a' and 'm' is:

Options

A. `(4m)/a^(3)`
B. `(2m)/a^(3)`
C. `m/a^(3)`
D. `m/(2a^(3))`

Answer

A

Explanation

Density `=("Mass of the unit cell")/("Volume of the unit cell")`
`=("No .of atoms" xx"Mass of each atom")/("Volume of the unit cell")`
`=(4xxm)/a^(3)` (in fcc arrangement no, of atoms `=4`)