A metal oxide has empirical formula `M_(0.96)O_(1.00)` What will be the percentage of `M^(2+)` ion in the crystal ?

Options

A. `90.67`
B. `91.67`
C. `8.33`
D. `9.33`

Answer

B

Explanation

Let the amount of `M^(2+)` ions in the `M_(0.96)O_(1.00)=x`
The amount of `M^(3+)` ions will be `=(0.96-x)`
As the metal oxide is neural,
`(+2)x+(+3)(0.96-x)+(-2)(1.00)=0`
or `2x+2.88-3x-2.00=0`
or `x=0.88`
`%` of `M^(2+)` ions in the crystal `=0.88/0.96xx100`
`=91.67%`