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KCl crystallises in the same type of lat...

KCl crystallises in the same type of lattice as does NaCl Given that `r_(Na^(+))//r_(Cl^(-))=0.55` and `r_(K^(+))//r_(Cl^(-))=0.74`, the ratio of the side of unit cell for KCl to that of NaCl is

A

`1.122`

B

`0.891`

C

`1.414`

D

`0.414`

Text Solution

Verified by Experts

The correct Answer is:
A
`(r_(Na^(+)))/(r_(Cl^(-)))=0.55,(r_(K^(+)))/(r_(Cl^(-)))=0.74`
`(r_(Na^(+)))/(r_(Cl^(-)))+1=1.55,` ....(i)
`(r_(K^(+)))/(r_(Cl^(-)))+1=1.74` ....(ii)
Dividing (ii) by (i)
`(r_(K^(+))+r_(Cl^(-)))/(r_(Na^(+))+r_(Cl^(-)))=(1.74)/(1.55)=1.122`
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KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

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