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Compound (A) C(4)H(10)O, is found to be...

Compound (A) `C_(4)H_(10)O`, is found to be soluble in sulphuric acid . (A) does not react with sodium or potassium permanganate. When (A) is heated with excess of HI, it is converted into a single alkyl halide. What is (A) ?

Text Solution

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(i) The molecular formula suggest that the compound [A] is either an alcohol or an ether
(ii) As the compound [A] is not oxidised with sodium or potassium permanganate, it is not an alcohol.
(iii) Since the compound [A] upon heating with excess of HI forms only one alkyl halide, it is a symmetrical ether and is diethylether.
`CH_(3)underset("Diethyl ether[A]")(CH_(2)-O-)CH_(2)CH_(3)+2HIrarrunderset("Ethyl iodide"")(2CH_(3)CH_(2)I)+H_(2)O`
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