The compound that neither forms semicarbazone nor oxime is

Options

A. `HCHO`
B. `CH_(3)COCH_(2)Cl`
C. `CH_(3)CHO`
D. `CH_(3)CONHCH_(3)`

Explanation

To determine the compound that neither forms semicarbazone nor oxime, we need to understand the nature of the compounds that typically undergo these reactions. Semicarbazones and oximes are formed from carbonyl compounds, which include aldehydes and ketones.

### Step-by-Step Solution:

1. **Identify the Reaction Types**:
- Semicarbazones are formed when carbonyl compounds (aldehydes and ketones) react with semicarbazide.
- Oximes are formed when carbonyl compounds react with hydroxylamine.

2. **List the Given Options**:
- Option A: HCHO (formaldehyde)
- Option B: C=O (generic ketone)
- Option C: Another aldehyde (not specified)
- Option D: An amide group (RCONH2)

3. **Analyze Each Option**:
- **Option A (HCHO)**: This is an aldehyde and will form both semicarbazone and oxime.
- **Option B (C=O)**: This represents a ketone and will also form both semicarbazone and oxime.
- **Option C (another aldehyde)**: Similar to option A, this will also form both semicarbazone and oxime.
- **Option D (amide group)**: Amides do not have a carbonyl group that can react to form semicarbazones or oximes.

4. **Conclusion**:
- Since options A, B, and C are carbonyl compounds and will form semicarbazones and oximes, the only option that does not is option D, which is an amide.

### Final Answer:
The compound that neither forms semicarbazone nor oxime is **Option D (amide group)**.