One mole of symmetrical alkene upon ozonolysis gives two moles of an aldehyde having the molecular mass `44 u`. Predict the alkene.

Options

A. Propene
B. But-1-ene
C. But-2-ene
D. Ethene.

Answer

C

Explanation

`C_(n)H_(2n)O = 44`
`12n + 2n + 16 = 44` or `14n = 28` or `n = 2`
The aldehyde is `C_(2)H_(4)O` and alkene which gives two moles of aldehydes upon ozonolysis must be `C_(4)H_(10)`. Since it is symmetrical, the alkene is but-2-ene. It can exist as cis and trans isomer. Out of these, trans isomer (but-2-ene) is more stable