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Describe the following i. Acetylation ...

Describe the following
i. Acetylation
ii. Cannizzaro reaction
iii. Cross aldol condensation
iv. Decarboxylation

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Crossed Aldol Condensation

(a) Give reasons : (i) CH_(3)-CHO is more reactive than CH_(3)COCH_(3) towards HCN. (ii) 4-nitrobenzoic acid is more acidic than benzoic acid. (b) Describe the following : (i) Acetylation (ii) Cannizzaro reaction. (iii) Cross aldol condensation.

Cross Cannizzaro reaction is

Aldol condensation reaction

Cross aldol condensation occurs between

Aldol condensation is a reaction given by

DINESH PUBLICATION-CARBOXYLIC ACIDS -ASSIGNMENT
  1. How will you convert propionic acid to ethyl amine ?

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  2. Give two chemical tests to distinguish between benzaldehyde and benzoi...

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  3. Describe the following i. Acetylation ii. Cannizzaro reaction i...

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  4. Why has monochloroethanoic acid higher pK(a) value than dichloroethano...

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  5. Write IUPAC name of CH(3)-underset(Cl)underset(|)(CH)-underset(COOH)un...

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  6. Give the formula of [A] and [B] CH(3)-overset(O)overset(||)C-OHovers...

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  7. How will you convert acetic acid into acetaldehyde ?

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  8. Write the reaction involved in the following : (i) Hell-Volhard zeli...

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  9. describe the following conversions : (i) Ethyl benzene to benzoic aci...

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  10. How will you convert benzoic acid into benzaldehyde ?

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  11. Write the reaction involved in the following : (i) Hell-Volhard zeli...

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  12. Arrange the following in order of decreasing of acid strenth indicated...

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  13. Draw the structure of hexane-1, 6-dioic acid.

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  14. Why is carboxylic acid a stronger acid than phenol ?

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  15. Complete the reaction : CH(3)COOHoverset(Cl(2)//P)rarr?

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  16. How will you convert benzoic acid into benzene ?

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  17. Complete the following reactions : (i) R-CH(2)COOHoverset(X(2)//"Red...

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  18. Predict the products of the following reactions : (i) C(6)H(5)CH(2)C...

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  19. Which reagent is used in the following conversion : CH(3)COOHoverset...

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  20. Account for the following : (i) Benzoic acid does not undergo Friede...

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